At an open bar there are 26 bottles: 6 vodkas, 5 Bacardi, 4 cognac, 4 Seagram’s, and 7 wines. If a guest randomly selects 5 bottles for his table, what is the probability that he will get 2 vodkas, 2 Seagram’s, and 1 cognac?

Kinda lost. would appreciate any help, thanks…

Because of a mistake in packaging, a case of 12 bottles of red wine was shipped to The Swamp Critter Inn. The case contained 5 Merlot and 7 Cabernet, each without labels. All of the bottles look alike and have an equal probability of being chosen. Three bottles are randomly selected.

Because of a mistake in packaging, a case of 12 bottles of red wine was shipped to The Swamp Critter Inn. The case contained 5 Merlot and 7 Cabernet, each without labels. All of the bottles look alike and have an equal probability of being chosen. Three bottles are randomly selected.

You have 8 bottles of zinfandel wine, 10 of merlot, and 12 of cabernet.

A. if you want to serve 3 bottles of zinfandel and serving order is important, how many ways are there to do this?
My Answer: Permentatiom(3,8)=336, but this question I am not sure if it is permentation or combination :-\

B. If 6 bottles of wine are to be randomly select from the 30 for serving how many ways are there to do this?
My Answer: 30choose6=593,775

C. if 6 bottles are randomly selected how many ways are there to obtain two bottles of each variety?
My Answer:
8choose2*10choose2*12choose2=83160

D. if 6 bottles are randomly selext what is the probability that this results in two bottles of each vaiety being chosen?
My Answer:
(8choose2*10choose2*12choose2)/(30choose6)=.140

E. if 6 bottles are randomly selected what is the probability that all of them are the same variety?
(8choose2)/(30choose6)*(10choose2)/(30choose 6)*(12 choose2)/(30choose6)=.00196

Please correct any wrong answers